Car A and Car B?

Arden Strachn: consider relatively car B to be at rest, when car A begins to accelerate with 2.4 m/s²[please note: if the the velocities of objects A and B are vₐ and vᵦ with respect to a stationary observer (neutral observer) on the ground surface, then the velocity of A relative to B is vₐ - vᵦ. this is as if B were at rest and only A were moving.] relative distance to be covered = 300 mvₐ - vᵦ = relative speed = 22 - 29 = -7 m/s (away from car B)relative acceleration = aₐ - aᵦ = 2.4 - 0 = 2.4 m/s²s = ut + ½at²=> 300 = -7t + ½(2.4)t²=> t² - 5.8333t - 250 = 0solving => t ~= 19 sCheck:actual speed of A when it overtakes = u + at = 67.6 m/ss = vₐᵥâ‚'t = 0.5[22 + 67.6]19 = 851 mdistance traversed for B = 19 x 29 = 551 m diff = 851-551 = 300 mhope this helps...Show more